Math alert:
\nMy spiral trees have 42 pixels. That means 42 x3 =126 LEDs per tree.
\n2 trees are connect each controller. That means controllers have 252 leds.
\nSo if we allow 20mA per LED. That comes to a total of
\n252 x 0.02 = 5.04A.
\n* controller fuses have to be 5 Amps. <\/p>\n
The spiral trees operate at 5v. To save on voltage drop I will run 12v to a small 10A dc dc converter that is located close to the controllers. 2 controllers will be connected to a single dc dc converter. That means it will supply 10.08Amps
\n10.08×5\/12= 4.2Amps at 12v. (Assuming perfect conversion)
\nRealistically there will be about 20 to 25% loss.
\n4.2 \/ 0.8= 5.25 Amps or 4.2\/0.75=5.6 Amps.
\n* dc dc converter
\n fuses have to be 5 Amps.<\/p>\n","protected":false},"excerpt":{"rendered":"
Math alert: My spiral trees have 42 pixels. That means 42 x3 =126 LEDs per tree. 2 trees are connect each controller. That means controllers have 252 leds. So if we allow 20mA per LED. That comes to a total … Continue reading